Questions & Answers for: SoftMath equation solver Computers & Internet

math algebra like 2x=4 or 6x=12 and what number do i devide both sides by to solver the equation Divide the first equation by 2, the second by 6 (i.e. the number that comes before the x)

....85/lb of nuts .55/lb of nuts want to sell 60lbs @.75/lb Convert what you know into a couple of equations. You'll need two equations because there are two unknowns. Call them X = pounds of nuts ...

x+y=10 x-y=2 use elimination The 1st equation contains a ‘+y’, while the 2nd contains a ‘-y’ term. they will cancel if added together, so we will add the equations to eliminate ‘y’. x-y=2 x+y=10 so ...

...+ 6y to the negative 1/2 power =37 let sqrt of y =x y to the power negative 1/2 = 1/ sqrt y so our equation becomes ( 6x + 1 / 6x ) = 37 36x^2 -222 x + 1 =0 the roots of above quadratic equation are ...

the product of a number and 47 yields -141 write the sentence as an equation. the product of a number and 47 yields -141 let number be x 47x = -141 is the equation of sentence given above x can be ...

solve the following equation for the indicated value of x: y = 4 sin x; for x = pie Since X = pi, (3.141592...) I'm going to assume the problem is in radians not degrees. Substitute pi in for X in the

y=7-x x-y=-3 Substitute (7 - X) in for Y in the 2nd equation and you get: X- (7 - X) = -3 => 2X - 7 = -3 => 2X = 4 Solve this for X and you get X =2. Plug X = 2 back into the first equation and ...

I don't see any easy to factor this so I'll either need to complete the square or use the quadratic equation. Using the quadratic equation, where A = 2, B = -19, and C = 22 x = [-(-19) +/- squareroot(

how to factor 5x^2-3x-10 ? This equation doesn't have whole number factors so you have to solve it by completing the square or using the quadratic equation. I used the quadratic equation 

find the radius of the equation x^2+y^2-2x-2y=14 Try casting the equation of the circle into the form (x-h)^2+(y-k)^2=R^2. Here (h,k) would be the center and R the radius.To do that complete the two ...