Questions & Answers for: sin

Trig Identities cosecӨ-sinӨ=cos²Ө/sinӨ Change csc to 1/sin. Find a common denominator and add the two left terms. 1/sin - sin = (1 -sin^2)/sin. Rewrite formula (1 - sin^2)/sin

(sin-cos)(sin+cos) help!! (sinX-cosX)(sinX+cosX) =(sin^2 - Cos^2X) =Sin^2X - (1-Sin^2X) =Sin^2X -1 + Sin^2X =2Sin^2X -1 Zulfikar Ali ali_zulfikar@yahoo.com 9899780221

...= 1/cot^4X + 1/cot^2X sec^4X- sec^2X = 1/cot^4X + 1/cot^2X RHS 1/cot^4X + 1/cot^2X =1/(Cos^4X/Sin^4X) + 1/(Cos^2X/Sin^2X) =Sin^4X/Cos^4X + Sin^2X/Cos^2X =Sin^4X/Cos^4X + Cos^2X.Sin^2X/Cos^4X ...

If f(x) = sin x, what is the 99th derivative of f(x)? Hello, Frankly my dear, who wants to compute the 99th derivative of sin(x)? d/dx(sin(x))= cos(x) d^2/dx^2 (sin(x))= d/dx( cos(x))=-sin(x) d^3/dx^3

how do you use the sin-1 You would press on the SIN key, "sin(" should come on the display, then enter the value, for example 3.5 or -1 so that the display shows sin(3,5) or sin(-1) for example. ...

1 + sinx = 2cos^2x Hii..this can be done as follow cos^2 x = 1 - sin^2 x--------(1) 2cos^2 x=1+ sin x 2cos^2 x - sin x -1=0 Substituting formula (1) 2(1 - sin^2 x) - sin x - 1 = 0 2sin^2 x + sin x - 1

Differentiate each of the following w.r.t.x; 29.sin2xsinx Use the rule for differentiating products of functions: ()' signifies derivative (29*sin(2X)*sin(X))'= (29)'*sin(2X)*sin(X) +29* ...

why limit of sin x is 1, when x tends to 0 ? Sin 0 = 0 Sin 90 = 1 Sin 180 = 0 Sin 270 = -1 Sin 360 = Sin 0 = 0 Is there an angle greater than 360??? Is there any greater value of Sine than 1 ???

find the trig function given its period cos 5 pi also need the answer for sin 19pi/6 cos(5PI)=cos(4PI+PI)=cos(PI)=-1sin(19PI/6)=sin(18PI/6+ PI/6)=sin(3PI +Pi/6)=sin(2PI+PI+PI/6)=sin(PI+PI/6)=sin(-PI/6

do you enter sin 30 to get answer or 30 sin Set the angle unit to degrees. Try sin (30)=, and 30 sin The correct answer is 0.5 Usually if pressing the sin key display sin( then you should use ...